Question

x square +x-2 into x-1​

Answer 1

Answer:

Given x2+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)

x=2a−b±b2−4ac

​​=2(1)−1±12−4{(a+2)(a+1)}

​​=2−1±1−4{−(a2+3a+2)

​​

x=2−1±1+4a2+12a+8

​​=2−1±4a2+12a+9

​​=2−1±(2a+3)2

​​=2−1±(2a+3)​

∴x=2−1+2a+3​ and x=2−1−2a−3​∴x=22a+2​ and x=2−2a−4​

x=a+1x=−(a+2)

∴ The roots of x2+x−(a+2)(a+1)=0 are (a+1) and −(a+2)

Step-by-step explanation:

HOPE IT HELPS U

Answer 2

Answer:

heya mate ☺

_____________uR aNsWeR :

$x ^{2} + (x - 2) \times (x - 1) \\ = x ^{2} + (x ^{2} - x - 2x + 2) \\ = x ^{2} + x ^{2} - x - 2x + 2 \\ = 2x ^{2} - 3x + 2$

♡ hope it helps u ♡

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