X square-x-6and xsquare+3x-18 have common factor (x-a) then find the value of a
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x2-x-6=0
x2-3x+2x-6=0
x(x-3)+2(x-3)=0
(x-3)(x+2)=0
x2+3x-18=0
x2+6x-3x-18=0
x(x+6)-3(x+6)=0
(x+6)(x-3)=0
therfore x-3 is common in both equations therefore a=3
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