Math, asked by ShaunakDutta2004, 9 months ago

x square + x - (a square + 3a + 2)=0

Answers

Answered by saptarshide12
1

Answer:

a+1

Step-by-step explanation:

x

2

+x−(a

2

+3a+2)=0

view step

ax^{2}+bx+c=0

\frac{-b±\sqrt{b^{2}-4ac}}{2a}

±

x^{2}+x-\left(a^{2}+3a+2\right)=0

x

2

+x−(a

2

+3a+2)=0

view step

ax^{2}+bx+c=0

1a1b-\left(1+a\right)\left(2+a\right)c\frac{-b±\sqrt{b^{2}-4ac}}{2a}

x=\frac{-1±\sqrt{1^{2}-4\left(-\left(a+1\right)\left(a+2\right)\right)}}{2}

x=

2

−1±

1

2

−4(−(a+1)(a+2))

view step

1

x=\frac{-1±\sqrt{1-4\left(-\left(a+1\right)\left(a+2\right)\right)}}{2}

x=

2

−1±

1−4(−(a+1)(a+2))

view step

-4-\left(1+a\right)\left(2+a\right)

x=\frac{-1±\sqrt{1+4\left(a+1\right)\left(a+2\right)}}{2}

x=

2

−1±

1+4(a+1)(a+2)

view step

14\left(1+a\right)\left(2+a\right)

x=\frac{-1±\sqrt{\left(2a+3\right)^{2}}}{2}

x=

2

−1±

(2a+3)

2

view step

\left(3+2a\right)^{2}

x=\frac{-1±|2a+3|}{2}

x=

2

−1±∣2a+3∣

view step

x=\frac{-1±|2a+3|}{2}

±-1|3+2a|

x=\frac{|2a+3|-1}{2}

x=

2

∣2a+3∣−1

view step

x=\frac{-1±|2a+3|}{2}

±|3+2a|-1

x=\frac{-|2a+3|-1}{2}

x=

2

−∣2a+3∣−1

view step

x=\frac{|2a+3|-1}{2}

x=

2

∣2a+3∣−1

x=\frac{-|2a+3|-1}{2}

x=

2

−∣2a+3∣−1

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