x square-x-k such that alpha-beta =9 find k
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x2-x-k=0
alpha beta =9
alpha beta =c/a
9=c/a
9= -k/1 (c=-k a=1)
9=-k
-9=k
Harshscigen:
its wrong
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x2-x-k
a=1
b=-1
c=k
alpha+ beta =-b/a
given:-
alpha-beta=9
so according to formula
alpha +beta=1
from given
let's
alpha=beta+9
substitute this value in above eqn we get
beta=-4
alpha-beta =9
substituting value of beta we get
alpha=5
hence
alpha*beta=c/a
-4×5=k/1
-20=k/1
hence k=-20
a=1
b=-1
c=k
alpha+ beta =-b/a
given:-
alpha-beta=9
so according to formula
alpha +beta=1
from given
let's
alpha=beta+9
substitute this value in above eqn we get
beta=-4
alpha-beta =9
substituting value of beta we get
alpha=5
hence
alpha*beta=c/a
-4×5=k/1
-20=k/1
hence k=-20
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