Question

x square. + ( y - 3√x2) 2 = 1​

Answer 1

Answer:

Step-by-step explanation:

The function definition is unclear. I am taking it as $x2+y−(3x1/2)2=1$  

The function is defined only in x=[0,1]

Now use matlab or octave to plot it

plot(x,sqrt(1-x.^2)+(3*sqrt(x)).^2)

Answer 2

The solutions are  $x = \frac{y-1 }{4}$ and $x = \frac{y+1 }{4}$

Step-by-step explanation:

Assuming the question to be $x^2 + (y-3\sqrt{x} ^2)^2 =1$

Solving the square root, inside the bracket, we obtain,

$x^2 + (y-3x} )^2 =1$

Bringing '1' on the left-hand side and shifting the bracket terms on the right-hand side, we obtain

$x^2 -1 = (y-3x} )^2$

The left-hand side is in the form of an algebraic identity, solving it we obtain

$(x+1) (x -1) = (y-3x} )^2$

Thus, the two roots can be

$(x+1) = (y-3x)$ and $(x -1) = (y-3x)$

Solving for x

$x+3x = y-1$ and $x+3x = y+1$

$4x = y-1$ and $4x = y+1$

$x = \frac{y-1 }{4}$and $x = \frac{y+1 }{4}$