Question

x square y square + x y z + X Y + Z​

Answer 1

x²+y²+xyz+xy+z

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Answer 2

Answer:

The factorisation of $x^{2} y z+x y^{2} z+x y z^{2}$is equal to$\mathbf{x y z}(\mathbf{x}$ $+y+z)$

Step-by-step explanation:

We have,

$x^{2} y z+x y^{2} z+x y z^{2}$

To find, the factorisation of $x^{2} y z+x y^{2} z+x y z^{2}=$ ?

$\therefore x^{2} y z+x y^{2} z+x y z^{2}$

$=x(x y z)+y(x y z)+z(x y z)$

Taking xyz as common, we get

$=x y z(x+y+z)$

$\therefore$The factorisation of $x^{2} y z+x y^{2} z+x y z^{2}=\mathbf{x y z}(\mathbf{x}+\mathbf{y}+\mathbf{z})$

Thus, the factorisation of $x^{2} y z+x y^{2} z+x y z^{2}$is equal to $\mathbf{x y z}(\mathbf{x}+\mathbf{y}+\mathbf{z}) .$

X square y square + x y z + X Y + Z​

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