Question

(x squared+3x+2)dy/dx+(2x+1)y=(xy+2y) squared answer in bernoulli's differential equations​

Answer 1

y’ *(x-1)=x^(2) +3x+2; => y’ = [x^2 +3x+2] / (x-1); Use the long Division on RHS:

y’=[x^2 +3x+2] / (x-1) = x +2 +4 / (x+2); Now you can integrate both sides:

y = x^2 / 2 +2x +4 ln(x+2)+C ;