Math, asked by tilakbang15magpd1kjo, 1 year ago

x squared minus root 3 x minus 6

Answers

Answered by gaurav2013c
124

 {x}^{2}  -  \sqrt{3} x - 6 \\  \\  =  {x}^{2}  - 2 \sqrt{3} x  +  \sqrt{3} x - 6 \\  \\  = x(x - 2 \sqrt{3} ) +  \sqrt{3} (x - 2 \sqrt{3} ) \\  \\  = (x - 2 \sqrt{3} )(x +  \sqrt{3} )
Answered by abhi569
52
 {x}^{2} - \sqrt{3} x - 6 \\ \\ = > {x}^{2} - (2 \sqrt{3} - \sqrt{ 3 } )x - 6 \\ \\ = > {x}^{2} - 2 \sqrt{3} x + \sqrt{3} x - 6 \\ \\ = > x(x - 2 \sqrt{3} ) + \sqrt{3} (x -2 \sqrt{3} ) \\ \\ = > (x - 2 \sqrt{3} )( x + \sqrt{3} )
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