Question

x squre+8x+12=0solve this is equation ​

Answer 1

$x {}^{2} + 8x + 12 = 0$

$x {}^{2} + (6 + 2)x + 12 = 0$

$x {}^{2} + 6x + 2x + 12 = 0$

$x(x + 6) + 2(x + 6) = 0$

$(x + 2)(x + 6) = 0$

$either$

$x + 2 = 0$

$x = - 2$

$or$

$x + 6 = 0$

$x = - 6$

Answer 2

$\underline \red{solution}: - \\ \\ = > {x}^{2} + 8x + 12 \\ \\ = > {x}^{2} + 6x + 2x + 12 \\ \\ = > x(x + 6) + 2(x + 6) \\ \\ = > (x + 6)(x + 2) \\ \\ = > x + 6 \: \: or \: \: x + 2 \\ \\ = > x = - 6 \: \: or \: \: x = - 2 \\ \\ \fbox \red{ \: i \: hope \: it \: helps \: you .}$