X
T
10.5 cm
In the above figure, XLMT is a rectangle. LM = 21 cm, XL = 10.5
cm. Diameter of the smaller semicircle is half the diameter of the
larger semicircle. Find the area of non-shaped region.
Help me asap
Answers
Answer:
Given:
XLMT is a rectangle.
Also,
XL = 10. 5 cm
LM = 21cm
Diameter of smaller circle is half the diameter of larger circle ( Given)
Let the diameter of larger circle = d ( Assumption)
Then, Diameter of smaller circle = d/2
From the figure,
Sum of two diameters = LM
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So,
Diameter of larger circle = 14 cm
Radius of larger circle = 7cm.
Diameter of smaller circle = 7 cm
Radius of smaller circle = 3.5 cm.
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Area of rectangle XLMT
= Length × Breadth
= XL × LM
= 21 × 10.5
= 220.5 cm²
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Area of semi circle = 1/2πr²
Now,
Area of larger semi circle = 1/2 ( 22/7) ( 7²) = 11 ( 7) = 77cm²
Area of smaller semi circle = 1/2 ( 22/7)(7/2)² = 77/4 = 19.25cm²
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Area of unshaded region = Area of rectangle XLMT - Area of two semi circles
= 220.5 - 77 - 19. 25
= 124.25 cm²
Therefore, Area of unshaded region is 124.25cm²