X=t^3+3t^2+2t thenfind the velocity at time of 3 seconds
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Answered by
1
Answer:
hey mate here is ur ans
Explanation:
x = t³+3t²+2t
velocity is the rate of change of distance
dx/dt = 3t²+6t+2
at t = 3
so dx/dt = v = 3(3)²+6(3)+2 = 27+18+2 = 47 m/s
hope it help u
Answered by
0
Answer:
Explanation:
Differentiating displacement with time gives velocity so answer is 47 m per sec
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