x takes 2 1/2 hours more time than that taken by y to cover certain distance. if x doubles his speed he can cover the same distance in 1 1/2 hours less than the time taken by y for same distance then how much time does y required to cover two-third of same distance
Answers
Answer:
1 (1/3) hours
Step-by-step explanation:
Let
D be the Distance,
x be Speed of X,
y be the Speed of Y
Condition 1: X takes 2 1/2 hours more time than that taken by y to cover certain distance.
D/x - D/y = 2.5 take it as first equation.
Condition 2:if X doubles his speed he can cover the same distance in 1 1/2 hours less than the time taken by Y for same distance
Similarly, D/y - D/2x = 1.5 take it as second equation.
Solve the above equation :
2D - D / 2x = 1
Therefore Distance D = 2x
Therefore time taken by Y required to cover two-third of same distance
Time = Distance / speed
= 2x * (2/3) / x
= 2x * (2/3) * (1/x)
= 4/2
Time = 1 (1/3) hours
Answer:
3(2/3)
Step-by-step explanation:
Tx=Ty+2.5
Tx/2=Ty-1. 5
Ty=5.5
S is indirectly proportional to 1/T
10=100/T, 10=50/T
T=10 hrs, T=5 hrs
5.5*2/3
11/3=3(2/3)