x takes 3 hours more than y to walk 30 km. But if x doubles his pace, he is ahead of y by 1
hours. Find their speeds of walking.
Answers
Answer:
The question says that time taken by X is 3 hrs more than Y to complete a distance of 30 km.
So, if speed of X and Y are x km/h and y km/h respectively, then
⇒ 30/x = 3 + 30x/4
⇒ 30/x - 30/y = 3
⇒ 10/x - 10/y = 1
Taking 1/x as u and 1/y as v, we get
→ 10u - 10v = 1 ___(1)
Now, if X doubles it's speed means 2x km/h then he will complete distance 3/2 hrs before than Y.
⇒ 30/2x = 30/y - 3/2
⇒ 30/2x - 30/y = - 3/2
⇒ 10/2x - 10/y = - 1/2
⇒ 10u/2 - 10v = - 1/2
→ 5u - 10v = - 1/2 ___(2)
By subtracting eq(1) by (2) we get,
⇒ 5u = 1 + 1/2
⇒ u = 3/10
Then, 10(3/10) - 10v = 1
⇒ - 10v = - 2
⇒ v = 1/5
Since 1/x = u and 1/y = v,
→ x = 10/3 km/h and y = 5 km/h
Hence speed of X is 10/3 km/h and Y = 5 km/h.
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Explanation: