Question

X takes 4 days to complete one third of a job, y takes 3 days to complete one sixth of the


same job and z takes 5 days to complete half of the job.if all of them work together for 3 days and x and z quit, how long will it take for y to complete the remaining work do

Answer 1

5.1 days. x=1/12 y=1/18 z =1/10. when all three work for 3 days 129/180 work is done leaving 51/180 of the work. This can be done by y in 5.1 days.

Answer 2

Answer:

5.1 days

Step-by-step explanation:

X completes work in 4 days = $\frac{1}{3}$

X completes work in 1 day = $\frac{1}{3 \times 4}=\frac{1}{12}$

Y completes work in 3 days = $\frac{1}{6}$

Y completes work in 1 day = $\frac{1}{6 \times 3}=\frac{1}{18}$

Z completes work in 5 days = $\frac{1}{2}$

Z completes work in 1 day = $\frac{1}{2 \times 5}=\frac{1}{10}$

So, They do work together in 1 day = $\frac{1}{12}+\frac{1}{18}+\frac{1}{10}$

                                                          = $\frac{43}{180}$

So, They do work together in 3 days = $\frac{43}{180} \times 3$

                                                            = $\frac{129}{180}$

Remaining work = $1-\frac{129}{180} =\frac{17}{60}$

Now remaining work has to be done by Y only

Y completes  $\frac{1}{6}$ work in days = 3

Y completes whole work in days = $\frac{3}{\frac{1}{6}}$

Y completes  $\frac{17}{60}$ work in days = $\frac{3}{\frac{1}{6}} \times \frac{17}{60}$

                                                                                = $5.1$

Hence y will tale 5.1 days to complete the remaining work .