Chinese, asked by engrriaz64, 5 months ago

x=tanx by Newtown Rephson method​

Answers

Answered by Anonymous
3

We need to use an iterative method to solve this problem, and I choose to use Newton-Raphson for this equation which can also be written as x=tan(x).

Clearly the roots of tan(x)−x are given by the intersections of y=x and y=tan(x). So the first 3 roots are around 3π/2, 5π/2, and 7π/2.

Here is my iteration scheme so far with x0=3π/2:

xn+1=xn−f(xn)f′(xn)=xn−xn−tan(xn)1−1cos2(xn)

Answered by Anonymous
0

Answer:

Explanation:  We need to use an iterative method to solve this problem, and I choose to use Newton-Raphson for this equation which can also be written as x=tan(x).

Clearly the roots of tan(x)−x are given by the intersections of y=x and y=tan(x). So the first 3 roots are around 3π/2, 5π/2, and 7π/2.

Here is my iteration scheme so far with x0=3π/2:

xn+1=xn−f(xn)f′(xn)=xn−xn−tan(xn)1−1cos2(xn)

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