Math, asked by parvez5124504, 2 months ago

X
x {}^{2}  - 2x =  - 2(3 - x)

Answers

Answered by BrainlyArnab
0

Answer:

Equation haven't any real zeroes

Step-by-step explanation:

 {x}^{2}  - 2x =  - 2(3 - x) \\  =  >  {x}^{2}  -  2x =  - 6 + 2x \\  =   >  {x}^{2}  - 2x - 2x =  - 6 \\  =  >  {x}^{2}  - 4x =  - 6 \\  =  >  {x}^{2}  - 4x + 6 = 0

Now it is in the standard form of quadratic equation (ax² + bx + c), here,

a = 1

b = -4

c = 6

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Now we can find the zeroes of the zeroes of this quadratic equation, But first we will check that zeroes are real or imaginary by discriminant.

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Discriminant = - 4ac

= (-4)² - 4(1)(6)

= 16 - 24

= -8

Because discriminant < 0, so this equation haven't any real zeroes, zeroes are imaginary.

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More information :-

When,

  • Discriminant < 0, so zeroes are unreal and imaginary.
  • Discriminant = 0, so zeroes are real and equal.
  • Discriminant > 0, so zeroes are real and unequal.

Discriminant = - 4ac (for quadratic equation)

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An quadratic equation have not more than 2 zeroes.

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Formula to find zeroes of quadratic equation -

 \frac{ - b ± \sqrt{ {b}^{2} - 4ac } }{2a} \\

hope it helps.

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