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Equation haven't any real zeroes
Step-by-step explanation:
Now it is in the standard form of quadratic equation (ax² + bx + c), here,
a = 1
b = -4
c = 6
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Now we can find the zeroes of the zeroes of this quadratic equation, But first we will check that zeroes are real or imaginary by discriminant.
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Discriminant = b² - 4ac
= (-4)² - 4(1)(6)
= 16 - 24
= -8
Because discriminant < 0, so this equation haven't any real zeroes, zeroes are imaginary.
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More information :-
When,
- Discriminant < 0, so zeroes are unreal and imaginary.
- Discriminant = 0, so zeroes are real and equal.
- Discriminant > 0, so zeroes are real and unequal.
Discriminant = b² - 4ac (for quadratic equation)
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An quadratic equation have not more than 2 zeroes.
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Formula to find zeroes of quadratic equation -
hope it helps.
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