Question

x
${x {}^{2} - 2x} - 8 \\ {4s}^{2} - 4s + 1 \\ {3x}^{2} - x - 4$
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Answer 1

here is ur answer

x²-2x-8

x²-4x+2x-8

x(x-4)+2(x-4)

(x-4)(x+2)

4s²-4s+1

4s²-2s-2s+1

2s(2s-1)-1(2s-1)

(2s-1)(2s-1)

3x²-x-4

3x²-4x+3x-4

x(3x-4)+1(3x-4)

(3x-4)(x+1)

★Hope it helps you!!!