Question

x
${x}^{2} - 4x - 165$
find the zero of the polynomial​

Answer 1

Answer:

${x}^{2} - 4x - 165 \\ {x}^{2} - (15 - 11)x - 165 \\ {x}^{2} - 15x + 11x - 165 \\ x(x - 15) + 11(x - 15) \\ (x - 15)(x + 11) \\ x - 15 = 0 \\ x = 15 \\ \\ x + 11 = 0 \\ x = - 11$

Hence it two zeros are 15 and - 11

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