x
![{x}^{2} + 5 lxl + 4 = 0 {x}^{2} + 5 lxl + 4 = 0](https://tex.z-dn.net/?f=+%7Bx%7D%5E%7B2%7D++%2B+5+lxl+%2B+4+%3D+0)
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Answer:
(x+1)(x+4)=0
=x=-1,-4
Step-by-step explanation:
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