Math, asked by devendra8571, 1 year ago

x
 {x}^{2} + 7 + 12

Answers

Answered by Hiteshbehera74
0

x²+7x+12 = 0

x²+3x+4x+12 = 0

x(x+3)+4(x+3) = 0

(x+3)(x+4) = 0

∴ x = -3,-4

Answered by Anonymous
0

Answer:

 {x}^{2}+ 7 + 12

 {x}^{2}+ 4x + 3x + 12

 x (x + 4) + 3 (x + 4)

 (x + 4) (x + 3)

 x = - 4

 x = - 3

HOPE IT HELPS YOU BUDDY.....

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