x
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Answered by
1
x^2 - 8x - 16 = 0
=> x^2 - 4x - 4x - 16 = 0
=> x(x-4) - 4(x-4) = 0
=> (x-4)(x-4) = 0
x = 4
=> x^2 - 4x - 4x - 16 = 0
=> x(x-4) - 4(x-4) = 0
=> (x-4)(x-4) = 0
x = 4
Answered by
0
ques. find "x"
given:
x² - 8x - 16 = 0
--> x² - 4x - 4x - 16 = 0
--> x(x-4) - 4(x-4) = 0
--> (x-4)(x-4)=0 ("x" cross the another "x" no value of 0)
--> 4.
hence the answer is 4.
thanks
given:
x² - 8x - 16 = 0
--> x² - 4x - 4x - 16 = 0
--> x(x-4) - 4(x-4) = 0
--> (x-4)(x-4)=0 ("x" cross the another "x" no value of 0)
--> 4.
hence the answer is 4.
thanks
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