Math, asked by pranav166, 1 year ago

x
x { }^{2}  - 8x - 16 = 0

Answers

Answered by gaurav2013c
1
x^2 - 8x - 16 = 0

=> x^2 - 4x - 4x - 16 = 0

=> x(x-4) - 4(x-4) = 0

=> (x-4)(x-4) = 0

x = 4
Answered by Anonymous
0
ques. find "x"

given: 
 x² - 8x - 16 = 0
--> x² - 4x - 4x - 16 = 0
--> x(x-4) - 4(x-4) = 0
--> (x-4)(x-4)=0 ("x" cross the another "x" no value of 0)
--> 4.

hence the answer is 4.

thanks
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