Question

X
${x}^{2} + \sqrt{2} x - 4 = 0$
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Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

=> x = -2√2 , √2

Step-by-step explanation:

=> x² + √2 x - 4 = 0

=> x² + 2√2 x - √2 x - 4 = 0

=> x(x + 2√2) -√2(x + 2√2)=0

=> (x + 2√2)(x - √2) =0

So either

=> x = √2

Or

=> x = - 2√2

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