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Question :
Solve for x in the given equation ;
x² - 5|x| + 6 = 0
Answer :
x = ±2 , ±3
Solution :
Here ,
The given equation is ;
x² - 5|x| + 6 = 0
The given equation can be rewritten as ;
|x|² - 5|x| + 6 = 0 [ °•° x² = |x|² ]
Now ,
Putting |x| = y , the above equation will become ;
y² - 5y + 6 = 0
Clearly ,
The above equation is quadratic in y .
Now ,
=> y² - 5y + 6 = 0
=> y² - 2y - 3y + 6 = 0
=> y(y - 2) - 3(y - 2) = 0
=> (y - 2)(y - 3) = 0
=> Either (y - 2) = 0 or (y - 3) = 0
• If (y - 2) = 0 , then
=> y = 2
=> |x| = 2
=> x = ±2
• If (y - 3) = 0 , then
=> y = 3
=> |x| = 3
=> x = ±3
Hence ,
x = ±2 , ±3
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