Question

x to the power 6 minus 7 x cube minus 8

Answer 1

Hey dear heree is your answer...
X^6 -x^3 -8x^3 -8

= x^3 × ( x^3+1) - 8 ( x^3+1)

= (x^3+1) × (x^3 -8)

▪Here by using (a^3+b^3)= (a+b) {a^2-ab+b^2}
(x+1)×(x^2-x+1)×(x-2)×(x^2+2x+4).......

Hope its helpfullll.... Mark me as brainliest...

Answer 2

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" x^6 - 7x^3 - 8 "
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=x^6 - 8x^3 + x^3 - 8


=x^3( x^3 - 8) + 1 (x^3 - 8 )


=(x^3 + 1 ) (x^3 - 8 )


={ x^3 + 1 } { (x)^3 - (2)^3 }


=(x^3 + 1 ) (x - 2 ) (x^2 + 2x + 4 )


={(x)^3 + (1)^3 } (x - 2) (x^2 + 2x + 4 )


=(x +1 ) (x^2 - x +1) (x -2 ) (x^2 + 2x + 4 )


=(x+ 1) (x - 2 )( x^2 - x + 1 ) (x^2 + 2x + 4 )
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|| hope helps ||
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