Question

(x to the power a+b ) a-b. (x to the power b+c ) b-c. ( x to the power c+a ) c-a

please solve it fast ​

Answer 1

Step-by-step explanation:

since the base is same that is 'x' therefore according to the laws of exponents the powers can be added as

$x {}^{a { }^{2} - b {}^{2} + b { }^{2} - c {}^{2} + c {}^{2} - a {}^{2} }$

(a+b)( a-b) = a² - b²

(b+c)(b-c) = b² - c²

(c+a)(c-a) =c² - a²

then all the powers will get cancelled it will be as

$x {}^{0}$

acc to laws of exponents anything raise to power is 1 therefore your answer to this question is 1