x to the power Cube + 13 x to the power square + 32 X + 20 if it is given that X + 2 is its factor
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Given expression, x³ + 13x² + 32x + 20.
Given that (x + 2) is factor.
So, let's divide x³ + 13x² + 32x + 20 by (x + 2) to get the remaining factors for the expression.
x + 2 ) x³ + 13x² + 32x + 20 ( x² + 11x + 10
- x³ + 2x²
-------------------
11x² + 32x
- 11x² + 22x
----------------------
10x + 20
- 10x + 20
--------------------
0
Now let's factorise the quotient, x² + 11x + 10
x² + 11x + 10 = x² + 10x + x + 10
= x ( x + 10 ) + 1 ( x + 10 )
= ( x + 10 ) ( x + 1 )
∴ x³ + 13x² + 32x + 20 = ( x + 1 ) ( x + 2 ) ( x + 10 )
Hope my answer helps you : )
Given that (x + 2) is factor.
So, let's divide x³ + 13x² + 32x + 20 by (x + 2) to get the remaining factors for the expression.
x + 2 ) x³ + 13x² + 32x + 20 ( x² + 11x + 10
- x³ + 2x²
-------------------
11x² + 32x
- 11x² + 22x
----------------------
10x + 20
- 10x + 20
--------------------
0
Now let's factorise the quotient, x² + 11x + 10
x² + 11x + 10 = x² + 10x + x + 10
= x ( x + 10 ) + 1 ( x + 10 )
= ( x + 10 ) ( x + 1 )
∴ x³ + 13x² + 32x + 20 = ( x + 1 ) ( x + 2 ) ( x + 10 )
Hope my answer helps you : )
KVaishu:
If my answer really helps you, then please grade it as the Brainliest answer.
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