Question

X upon 2 + 2 Y upon 3 is equal minus 1 and x minus y upon 3 equals to 3​

Answer 1

Answer:

$(x \div 2) + (2y \div 3) = - 1 \\ 3x + 4y = - 6 \: \: \: \: (eq1) \\ (x - y) \div 3 = 3 \\ x - y = 9 \: \: \: (eq2)$

Through substitution,

In eq2,

x=y+9. (eq3)

Putting eq3 in eq1,

3(y+9)+4y=-6

3y+27+4y=-6

7y+27=-6

7y=-6-27

7y=-33

y=-33/7

Putting (y=-33/7) in eq2,

x=-33/7+9

x=(-33+81)/7

x=48/7

Answer 2

Step-by-step explanation:

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