Question

X upon 2 + 2 y upon 3 is equal to minus 1 and x minus y upon 3 is equal to 3 by elimination method

Answer 1

Answer:

$\frac{x}{2} + \frac{2y}{3} = - 1 \: or \: 3x + 6y = - 6\\ \frac{x - y}{3} = 3 \: \: \: \: or \: \: x - y = 9$

multiply 2nd eqn by 6 and add both equation to eliminate y

$3x + 6x = 54 - 6 = 48 \\ x = \frac{16}{3}$

Similar eliminate x