Question

x varies directly as the cube root of y x=6 when y=8 find the value of x when y=64

Answer 1

$x = k \sqrt[3]{y} \\ x \div \sqrt[3]{64} = 6 \div \sqrt[3]{8} \\ x \div 4 = 6 \div 2 \\ x = 4 \times 3 \\ x = 12$