Question

x varies inversely as twice of y. given that when y =6 ,the value of x is 4 . find the value of x when y =8.​

Answer 1

Answer:

Step-by-step explanation:x=K(2y)

4=k(2×6)

K=1/3

Now

X=1/3×(2×8)

X=16/3

Answer 2

Answer:  The required value of x is $\dfrac{16}{3}$.

Step-by-step explanation:  Given that x varies inversely as twice of y. Also, when y is 6, the value of x is 4.

We are to find the value of x when y is 8.

According to the given information, we have

$y\propto 2x\\\\\Rightarrow y=k\times2x~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{where k is the constant of proportionality}]\\\\\Rightarrow y=2kx~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

When y = 6 and x = 4, then from equation (i), we have

$4=2k\times6\\\\\Rightarrow 4=12k\\\\\Rightarrow k=\dfrac{1}{3}.$

Substituting the value of k in equation, we get

$x=2\times\dfrac{1}{3}\times y\\\\\\\Rightarrow x=\dfrac{2}{3}y.$

Therefore, when y = 8, we get

$x=\dfrac{2}{3}\times8=\dfrac{16}{3}.$

Thus, the required value of x is $\dfrac{16}{3}$.