Math, asked by khanfaryal306, 11 months ago

X varies inversely as Y³. If X=16 when Y is 5 , find X when Y is 2

Answers

Answered by Anonymous
13

Answer:

x varies inversely as y^3

So x y^3 is constant

if x=16, y=5

So, xy^3 = 16(5)^3

=16(125)

= 2000

So, Value of x when y=2

= 2000/(2)^3

=2000/8

=250

So, X=250

#answerwithquality #BAL

Answered by Anonymous
7

Answer:

x varies inversely as y^3

So x y^3 is constant

if x=16, y=5

So, xy^3 = 16(5)^3

=16(125)

= 2000

So, Value of x when y=2

= 2000/(2)^3

=2000/8

=250

So, X=250

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