Question

X walks 6 km towards east from a point a and from the same point a, y walks 8 km towards south. How far are the two friends from each other now? (a) 14 km (b) 2 km (c) 10 km (d) 5 km

Answer 1

Thank you for asking this question. Here is your answer:

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X Walk in East = 6 km

Y walk in south = 8 km

We can see that  It makes a right angled triangle

Distance 2 = (62+82)

Distance 2 = 36+64

Distance = 10

10 is the final answer for this question.

If there is any confusion please leave a comment below.

Answer 2

Answer:

Option (c) 10 km is correct.

Distance between X and Y is 10 km

Step-by-step explanation:

Consider the given figure ΔABC,

Consider point A

X walks 6 km towards east from A and reaches a point B

Y walks 8 km towards south from A and reaches a point C

i.e., AB = 6

      AC = 8

We need to find the distance between these 2 friends, i.e., BC

We know that, In a right-angled triangle,

Using Pythagoras theorem,

hypotenuse² = base² + altitude²

i.e., BC² = AB² + AC²

⇒ BC² = 6² + 8²

⇒ BC² = 36 + 64

⇒ BC² = 100

⇒ BC = $\sqrt{100}$

⇒ BC = 10

∴ The distance between X and Y  is 10 km.

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