Question

X walks 6km towards east from a point a and from the same point a y walks 8km towards south

Answer 1

That's nice, two men just strolling in perpendicular directions, if you want to know the distance between them, it will be √(8*8 + 6*6) which is 10 km

Answer 2

The distance between x and y is 10 km.

Given:

x walks 6 km towards east from a point 'a' and from the same point 'a' y walks 8 km towards south  

To find:

How far are the two friends from each other now?

Solution:

Complete question:

X walks 6 km towards east from point a and from the same point a, y walks 8 km towards south. How far are the two friends from each other now? (a) 14 km (b) 2 km (c) 10 km (d) 5 km

Condition used:

According to the Pythagorean theorem, in a right-angled triangle

=> Hypotenuse² = Side² + Side²

Given that

x walks 6 km towards the east from point 'a'  

y walks 8 km towards the south from point 'a'

This can be represented as a figure as shown below

Draw a line by joining x and y

Here we will have a Right angle triangle axy  

Where ax = 6 cm and ay = 8 cm

By the given condition

=> Hypotenuse² = Side² + Side²

=> xy² = ax² + ay²

=> xy² = 6² + 8²

=> xy² = 36 + 64

=> xy² = 100 = 10²

=> xy = 10

Therefore,

The distance between x and y is 10 km

#SPJ6