X'works twice as fast as Y. If Y alone can complete a job in 18 days, find how many days will X and Y
together take to complete the job.
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Answered by
1
Answer:
6 days
Y alone can finish work in 18 days
X works twice as fast as Y
So, Days taken by X to finish the work= Y/2= 9
Days Taken by X & Y to finish the work together= 1(1/9+1/18)
= 1{(2+1)/18}
= 1(1/6)
= 6 days
Answered by
0
Answer:
I don't understand the question
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