Question

x-(x-1)/2=1-(x-2)/3
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Answer 1

Allow:

• (x−1)=a
• (x−2)=b
• (x−3)=c

1ab+1bc=23

⟹b(1ab+1bc)=b×23

⟹ac(1a+1c)=ac(2b3)

⟹3(a+c)=3(2abc3)

⟹3(a+c)=2abc

⟹3(x−1+x−3)=2abc

⟹3(2x−4)=2(x−1)(x−2)(x−3)

⟹(6x−12)+12=(2x3−12x2+22x−12)+12

⟹6x−6x=(2x3−12x2+22x)−6x

⟹2x(x2−6x+8)=0

⟹2x(x−2)(x−4)=0

x=0 or 4

Answer 2

Step-by-step explanation:

x-(x-1)/2=1-(x-2)/3

=> -(x-1)/2+(x-2)/3=1-x

=>{-3(x-1)+2(x-2)}/6=1-x

=> -3x+3+2x-4=6(1-x)

=> -x-1=6-6x

=> -x+6x=6+1

=> 5x=7

=>x=7/5