x(x-1)(x-2)(x-3)+8=0
Answers
Answered by
1
x(x-1)(x-2)(x-3)+8=0
x [ x ( - 1 * -2 *-3) + 8] = 0
x² - 6x + 8 = 0
x² - (4 + 2)x + 8 = 0
x² - 4x - 2x + 8 = 0
x (x - 4) -2(x - 4) = 0
(x - 4) (x -2) = 0
x = 4 or x = 2
Hope you like it please mark as brainliest.
x [ x ( - 1 * -2 *-3) + 8] = 0
x² - 6x + 8 = 0
x² - (4 + 2)x + 8 = 0
x² - 4x - 2x + 8 = 0
x (x - 4) -2(x - 4) = 0
(x - 4) (x -2) = 0
x = 4 or x = 2
Hope you like it please mark as brainliest.
ashish1949:
no this is wrong answer
now it is correct answer
Answered by
0
Hey mate ♥ here is ur answer :
HOPE THIS ANSWER WILL HELP U
PLEASE MARK IT BRAINLIEST
HOPE THIS ANSWER WILL HELP U
PLEASE MARK IT BRAINLIEST
Attachments:
plz solve whole question
Similar questions