x(x+1)(x+2)(x+3)/x(x+1)
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Answer:
x(x+1)= x²+x
(x+2)= x+2 ( same)
(x+3)= x+3 ( same)
=> x(x+1)(x+2)(x+3)/ x(x+1) = ( x²+x) ( x+2) ( x+3)/x(x+1)
= ( x²+x) ( x+2) ( x+3)/ ( x²+x)
= (x+2) ( x+3)
= ( x²+3x+2x+6)
= ( x²+5x+6)
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