Question

X(x+1)(x+2)(x+3)=y^2, show that it has no solution where x,y ∈ 0

Answer 1

Step-by-step explanation:

(x²+x)(x+2)(x+3)=y^2

x²+x+x+2+x+3=y^2

x²+3x+5=y^2

y^2=y²

4x²+5=y²

5=(y-4x)²

=(y-4x)²-5