(x) =x^2+2/x , then find the value of 2f (−1)
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x2+2=2x⇒x2−2x+2=0⟶1
To find
x4−x3+x2+2=x4+2x3+2x2+x3−x2+2=(x4−2x3+2x2)+(x3−2x2+2x)+(x2−2x+2)=x2(x2−2x+2)+x(x2−2x+2)+(x2−2x+2)=x2(0)+x(0)+0from⟶1=0
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