Question

x- x-2\3=1-x-3\4
can you solve in correct way​

Answer 1

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

• $x - \dfrac{x-2}{3} = 1 - \dfrac{x-3}{4}$

To Find:

• Value of x

Solution:

$\implies x - \dfrac{x-2}{3} = 1 - \dfrac{x-3}{4} \\ \\ \implies \dfrac{3x - x + 2}{3} = \dfrac{4 - x + 3}{4} \\ \\ \implies \dfrac{2x + 2}{3} = \dfrac{7 -x}{4} \\ \\ \implies 4(2x + 2) = 3(7 - x) \\ \\ \implies 8x + 8 = 21 - 3x \\ \\ \implies 8x + 3x = 21 - 8 \\ \\ \implies 11x = 13 \\ \\ \bold{\implies \dfrac{13}{11}}$

Hope It Helps!!

Answer 2

Thisi s right answer..

of your that question not this.