Question

{x(x+2x)}+{x(2-x)(5+x)}=0​

Answer 1

$SOLUTION$

$= > (x(x + 2x)) + (x(2 - x)(5 + x)) = 0 \\ \\ = > x((x + 2x) + (2 - x)(5 + x)) = 0 \\ \\ = > x + 2x + 10 + 2x - 5x - {x}^{2} = 0 \\ \\ = > 10 - {x}^{2} = 0 \\ \\ = > {x}^{2} - 10 = 0 \\ \\ = > {x}^{2} = 10 \\ \\ = > x = (+ \sqrt{10} ) \: \: \: (- \sqrt{10} )$

$HOPE \:IT \:HELPS$

Answer 2

Answer:

GIVEN FUNCTION :–

$(x(x + 2x)) +{x(2 - x)(5 + x)} = 0 \\ \\ (x)(3x) + x(10 - 5x + 2x - {x}^{2} ) = 0 \\ \\ (x)(3 {x} + 10 - 3x - {x}^{2} ) = 0 \\ \\ (x)( {x}^{2} - 10) = 0$

SO , THE SOLUTION –

$x = 0 \: </strong><strong>,</strong><strong>\: {x}^{2} - 10 = 0$

$x = 0 \: </strong><strong>,</strong><strong>\: x = \sqrt{10} \: </strong><strong>,</strong><strong> \: x = - \sqrt{10}$

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