Question

"x (x+3)-6=12find the vale​

Answer 1

$\huge\sf\underbrace\orange{Solution}$

x(x + 3) - 6 = 12

x² + 3x - 6 = 12 (Transpose 12 to LHS)

x² + 3x -6 -12 =0

x² + 3x - 18 = 0

It is a quadratic equation Now solve it Splitting the middle term!!

x² + 6x - 3x -18 =0

x (x + 6) -3(x + 6) = 0

Take common

(x +6) (x-3) =0

Now equate both to 0

x + 6 =0

x = -6

x -3 =0

x = 3

So,Required values of x are 3,-6

Answer 2

Question

x (x+3)-6=12 find the value of x

Answer

x (x+3)-6=12

$\leadsto \rm{x(x + 3) - 6 = 12}$

$\leadsto \rm{x ^{2} + (3x) - 6 = 12}$

$\leadsto \rm{x ^{2} + 3x- 6 - 12= 0}$

$\leadsto \rm{x ^{2} + 3x - 18= 0}$

$\leadsto \rm{x ^{2} + (6 - 3)x - 18= 0}$

$\leadsto \rm{x ^{2} + 6x - 3x - 18= 0}$

$\leadsto \rm{x(x + 6) - 3(x + 6)= 0}$

$\leadsto \rm{(x + 6)(x - 3)= 0}$

$\large \tt{Either}$

$\leadsto \rm{(x + 6) = 0}$

$\leadsto \rm{x = - 6}$

$\large \tt{Or}$

$\leadsto \rm{(x - 3)= 0}$

$\leadsto \rm{x = 3}$

$\tt{The \: value \: of \: x \: is \: ( - 6) \: or \: 3}$