X+√x= √3 then the value of x
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x+1x=3–√
(x+1x)3=(3–√)3
x3+1x3+3.x.1x.(x+1x)=33–√
x3+1x3+33–√=33–√
x3+1x3=0
x3=−1x3=>x6=−1
squaring, x12=1
(x6)3=(−1)3=>x18=−1
x18+x12+x6+1=−1+1−1+1=
hope it is helpful thank you
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