x(x ³- y³) + 3 xcy (x-y)
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Answer:
=3cx2y−3cxy2+x4−xy3
hope it helps
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x(x ³- y³) + 3 xcy (x-y)
Consider, (x+y)3−(x3+y3)=(x+y)3−[(x+y)(x2−xy+y2)]
=(x+y)[(x+y)2−(x2−xy+y2)]
=(x+y)[(x2+2xy+y2)−(x2−xy+y2)]
=(x+y)(3xy)
Clearly, 3xy is factor of (x+y)3−(x3+y3)
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