Math, asked by atharvatalati, 2 months ago

x-x/4-1/3=2+x/4 please tell me the answer of this question​

Answers

Answered by samuravadish
1

lets \: solve \: your \: equation \: step \: by \\ step

x -  \frac{x}{4}  -  \frac{1}{3}  = 2 +  \frac{x}{4}

step \: 1 \: : \: simplify \: both \: sides \:  \\ of \: equation

(x +  \frac{ - 1}{4} x) + ( \frac{ - 1}{3} ) =  \frac{1}{4} x + 2 \:  \\ (combine \: like \: terms)

 \frac{3}{4} x +  \frac{ - 1}{3}  =  \frac{1}{4} x + 2

step \: 2: \: subtract \:  \frac{1}{4}x \: from \: both \\ sides

 \frac{3}{4} x +  \frac{ - 1}{3}  -  \frac{1}{4} x =   \frac{1}{4} x + 2 -  \frac{1}{4}

 \frac{1}{2} x +  -  \frac{1}{3}  = 2

step \: 3 \: : add \:  \frac{1}{3}  \: to \: both \: sides

 \frac{1}{2} x +  \frac{ - 1}{3}  +  \frac{1}{3}  = 2 +  \frac{1}{3}

 \frac{1}{2} x =  \frac{7}{3}

step \: 4: \: multiply \: both \: sides \: by \:  \\ 2

2 \times ( \frac{1}{2} x) = 2 \times  \frac{7}{3}

 \frac{2}{2} x =  \frac{14}{3}

x =  \frac{14}{3} \:  (cancel \: both \: 2)

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