Question

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4. If 2x + y = 32 and 3x + 4y = 68, find the value of
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5. The sides of an equilateral triangle are (x + 3y) cm, (3x +​

Answer 1

Answer:

4. the answer is 8

Explanation:

2x+y=32.....eqn(1)

3x+4y=68....eqn(2)

Now, multiplying equn(1) by 4 on both sides, we get,

8x+4y=128.......equn(3)

subtracting equn(2) from equn(1)

8x+4y=128

-(3x+4y=68)

- -

or, 5x = 60

x= 60/5

x= 12

substituting the value of x in equn(1)

2*12+y= 32

y= 32-24

y= 8