Math, asked by aiswaryatt2005, 5 days ago

x:|x|=4,x²+16=0,x belongs to N in roster form​

Answers

Answered by kaursumeet693
2

Answer:

If

If x

If x2

If x2+

If x2+16

If x2+16=

If x2+16=0

If x2+16=0

If x2+16=0 x

If x2+16=0 x=

If x2+16=0 x=±

If x2+16=0 x=±√

If x2+16=0 x=±√−

If x2+16=0 x=±√−16

If x2+16=0 x=±√−16

If x2+16=0 x=±√−16 Explanation:

If x2+16=0 x=±√−16 Explanation:If

If x2+16=0 x=±√−16 Explanation:If a

If x2+16=0 x=±√−16 Explanation:If ax

If x2+16=0 x=±√−16 Explanation:If ax2

If x2+16=0 x=±√−16 Explanation:If ax2+

If x2+16=0 x=±√−16 Explanation:If ax2+b

If x2+16=0 x=±√−16 Explanation:If ax2+bx

If x2+16=0 x=±√−16 Explanation:If ax2+bx+

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0,

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0,

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, then

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=1

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4a

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac)

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac)

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1,

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1,b

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1,b=

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1,b=0

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1,b=0,

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1,b=0,c

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1,b=0,c=

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1,b=0,c=16

If x2+16=0 x=±√−16 Explanation:If ax2+bx+c=0, thenx=12a(−b±√b2−4ac) For x2+16=0 a=1,b=0,c=16

Answered by Ɍɛղgɔƙմ
13

Answer:

Thanks for your question...</h2><h2> \\ </h2><h2>Your  \: required  \: answer :</h2><h2></h2><h2> \\ x² + 16 = 0 \\ </h2><h2> \\ x² = -16</h2><h2> \\ x = √-16</h2><h2> \\ x = ± 4</h2><h2></h2><h2> \\ Brainliest Please

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