Question

X×X-5X+k=0 having distinct roots then the value of k is=?

Answer 1

X×X-5X+k=0
x² - 5x + k = 0
It is given that it had distinct roots so
Discriminant = D = 0
D = b² - 4ac
D = (-5)² - 4(1)(k)
0 = 25 - 4k
4k = 25
k = 25/4

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