Question

X*x-6ax+2 the equation has two real roots belongs to integer find the value of a

Answer 1

Answer:

Step-by-step explanation:

x2-6ax+2=0

a=1, b=-6a, c=2

D=b2-4ac

0=(-6a) 2-4(1) (2)

0=36a2-8

8=36a2

8/36=a2

√2/9=a

1/3√2=a