β(x)=β'(x) and β(1)=2 thenβ(3) equals
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B (x)=B'(x)
B (x)/B'(x)=1
now integrate both side
lnB (x)=x+c
now B(1)=2
so, ln2-1=c
now, B (3)=2e^2
B (x)/B'(x)=1
now integrate both side
lnB (x)=x+c
now B(1)=2
so, ln2-1=c
now, B (3)=2e^2
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